Given:
Distance further away from the mountain, d = 5 km
Angle of elevation from 1 st point, θ = 25° 10’
Angle of elevation from the 2 nd point, ϕ = 15 ° 20 ’
To find: Height of the mountain
Solution:
In the figure, Let A be the mountain top. C and D are points of observation.
In right angled Δ ABC,
tan 25° 10' = AB / BC
BC tan 25° 10’ = AB
BC = AB / tan (25° 10’)
BC = AB / 0.4699
In right angled Δ ABD,
tan 15° 20' = AB / BD
tan 15° 20' = AB (BC + 5) ……………………………… [BD = BC + 5]
0.2742 = AB / (BC + 5)
Substituting BC = AB / 0.4699
= 0.2742
0.4699 AB = 0.2742(AB + 2.3495)
0.4699 AB - 0.2742 AB = 0.644
0.1957 AB = 0.644
AB = 0.644 / 0.1957
= 3.29 km
∴ The height of a mountain is 3.29 km.