Evaluate the integrals using substitution.
Given: 
Let x + 2 = t2 ⇒ dx = 2t dt
And x = t2 -2
when, x = 0, t = √2 and when x = 2, t = 2
so,
5
Evaluate the integrals using substitution.
Given:
Let x + 2 = t2 ⇒ dx = 2t dt
And x = t2 -2
when, x = 0, t = √2 and when x = 2, t = 2
so,