Evaluate the integrals using substitution.
Given: 
Let x + 1 = t
⇒ dx = dt
When x = -1, t = 0 and when x = 1, t = 2
because,
8
Evaluate the integrals using substitution.
Given:
Let x + 1 = t
⇒ dx = dt
When x = -1, t = 0 and when x = 1, t = 2
because,