Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
+I effect donates e- . Br group will show +I effect along the chain but as I effect is distance dependent effect it will die as the distance increase.+I effect of alkyl group will reduce the acidity of a compound whereas –I effect will increase the acidity,I effects are distance dependent, correct order will be (CH3)2CHCOOH< CH3CH2CH2COOH< CH3CH(Br)CH2COOH < CH3CH2CH(Br)COOH.