Arrange the following in increasing order of their basic strength:
CH3NH2, (CH3)2NH, (CH3)3N, C6H5NH2, C6H5CH2NH2.
In C6H5NH2 , N is directly attached to the ring that causes delocalization of electrons of the benzene ring. Whereas in case of C6H5CH2NH2 it is not directly connected to benzene ring Hence it has more basic strength.
Due to –I effect of (CH3)3– a group it has more basic strength than C6H5CH2NH2. Hence final order will be C6H5NH2< C6H5CH2NH2<(CH3)3N< CH3NH2< (CH3)2NH