The photograph of a house occupies an area of 1.75 cm 2 on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m 2 . What is the linear magnification of the projector-screen arrangement.

Question

Philoid · Accepted Answer

Given: Area of photograph of house (A_object) - 1.75 cm²

Area of image formed on screen (A_image)- 1.55 m² = 1.55 x 10⁴ cm²

Formula: Areal magnification (m) = A_image / A_object ,

where A_imageand A_object are the areas of image and object respectively.

Since the dimension of areal magnification is L² and dimension of linear magnification is L,

Linear magnification (m_l) = √m

m = (1.55 × 10⁴ cm²)/(1.75 cm²)

⇒ m_l = 94.1 (report upto 3 significant figures only)

The photograph of a house occupies an area of 1.75 cm2 on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m2. What is the linear magnification of the projector-screen arrangement.

The photograph of a house occupies an area of 1.75 cm² on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m². What is the linear magnification of the projector-screen arrangement.