The position-time (x-t) graphs for two children A and B returning from their school O to their homes P and Q respectively are shown in Fig. 3.19. Choose the correct entries in the brackets below;
(a) (A/B) lives closer to the school than (B/A)
(b) (A/B) starts from the school earlier than (B/A)
(c) (A/B) walks faster than (B/A)
(d) A and B reach home at the (same/different) time
(e) (A/B) overtakes (B/A) on the road (once/twice).
From the given Figure 3.19,
(a) Distance OP < OQ. So, A lives closer to the school than B.
(b) From School, starting time for A is Zero whereas B has some finite value t. So, A starts from the school earlier than B.
(c) Slope represents the velocity in uniform motion.
Slope of B > Slope of A
So, B walks faster than A.
(d) Since, the end point of time for B has less value than A. A and B reaches their homes at different times. B reach home before A.
(e) Only one point of intersection occurs in graph and we know that B is faster than A. So, B overtakes A once in whole journey.