A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25s, what is the magnitude and direction of acceleration of the stone?

Given:


Length of the string = l= 80cm = 0.8m



Horizontal circular motion of a stone tied to a string



= H



=(2××) rad/s


ω = rad/s


Explanation: The object is in circular motion. Therefore, magnitude of acceleration produced in the stone is equal to the magnitude of centripetal acceleration.


Centripetal acceleration = ac = ω2r


= m/s2


= 9.91 m/s2


Acceleration is towards the centre of the circle along the radius.


Centripetal acceleration is 9.91m/s2 towards the centre of the circle along the radius.


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