A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 m s-1. How long does the body take to stop?
The Newton’s second law of motion states that,
F = m× a
⇒ a = F / m
Where,
F is the force on the body,
m is the mass of the body and
a is the acceleration of the body.
Given,
F = -50 N
The negative sign is because the force applied to the body is retarding and acts in the opposite direction to the motion of the body.
m= 20 kg
Thus, the acceleration is
The first equation of motion at time t, can be written as,
v = u + at
where,
v is the final velocity,
u is the initial velocity,
a is the acceleration of the body.
For the body to stop the final velocity must be equal to zero, thus the equation becomes,
Ans: the total time taken by the body to come to rest is 6 seconds.