A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 m s-1. How long does the body take to stop?

The Newton’s second law of motion states that,

F = m× a


a = F / m


Where,


F is the force on the body,


m is the mass of the body and


a is the acceleration of the body.


Given,


F = -50 N


The negative sign is because the force applied to the body is retarding and acts in the opposite direction to the motion of the body.


m= 20 kg


Thus, the acceleration is



The first equation of motion at time t, can be written as,


v = u + at


where,


v is the final velocity,


u is the initial velocity,


a is the acceleration of the body.


For the body to stop the final velocity must be equal to zero, thus the equation becomes,



Ans: the total time taken by the body to come to rest is 6 seconds.


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