In three moles of ethane (C2H6), calculate the following:
(i) Number of moles of carbon atoms.
(ii) Number of moles of hydrogen atoms.
(iii) Number of molecules of ethane.
In 1 mole of ethane (C2H6), it is seen that 2 moles of carbon and 6 moles of hydrogen is present.
(i) Since three moles of ethane is present,
So, Number of moles of carbon present = 3×2
= 6
Therefore 6 moles of carbon is present in 3 moles of ethane.
(ii) Since three moles of ethane is present,
So, Number of moles of hydrogen present = 3×6
= 18
Therefore 18 moles of hydrogen is present in 3 moles of ethane.
(iii) 1 mole of ethane contains 6.023×1023 molecules of ethane [By Avogadro’s Law]
Therefore, Number of molecules if ethane in 3 moles of ethane
= 3×6.023×1023
= 18.069×1023
Therefore, Number of molecules of ethane present in 3 moles of ethane is 18.069×1023