In three moles of ethane (C2H6), calculate the following:

(i) Number of moles of carbon atoms.


(ii) Number of moles of hydrogen atoms.


(iii) Number of molecules of ethane.

In 1 mole of ethane (C2H6), it is seen that 2 moles of carbon and 6 moles of hydrogen is present.


(i) Since three moles of ethane is present,


So, Number of moles of carbon present = 3×2


= 6


Therefore 6 moles of carbon is present in 3 moles of ethane.


(ii) Since three moles of ethane is present,


So, Number of moles of hydrogen present = 3×6


= 18


Therefore 18 moles of hydrogen is present in 3 moles of ethane.


(iii) 1 mole of ethane contains 6.023×1023 molecules of ethane [By Avogadro’s Law]


Therefore, Number of molecules if ethane in 3 moles of ethane


= 3×6.023×1023


= 18.069×1023


Therefore, Number of molecules of ethane present in 3 moles of ethane is 18.069×1023


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