What is the concentration of sugar (C12H22O11) in mol L–1 if its 20 g are dissolved in enough water to make a final volume up to 2L?

Given:

Mass of sugar = 20g


Volume of solution = 2 L


Atomic Mass of Hydrogen = 1g


Atomic Mass of Oxygen = 16g


Atomic Mass of Carbon = 12g


So Molecular Mass of sugar = [12×12] + [22×1] + [16×11]


= 144 +22 + 176


= 342 g


Number of moles of sugar = [Mass of sugar]/ Molecular Mass of sugar


= 20/342


= 0.05848


Molarity, Mo



= 0.0292 mol/L


≈ 0.029 mol/L


12