What is the concentration of sugar (C12H22O11) in mol L–1 if its 20 g are dissolved in enough water to make a final volume up to 2L?
Given:
Mass of sugar = 20g
Volume of solution = 2 L
Atomic Mass of Hydrogen = 1g
Atomic Mass of Oxygen = 16g
Atomic Mass of Carbon = 12g
So Molecular Mass of sugar = [12×12] + [22×1] + [16×11]
= 144 +22 + 176
= 342 g
Number of moles of sugar = [Mass of sugar]/ Molecular Mass of sugar
= 20/342
= 0.05848
Molarity, Mo
= 0.0292 mol/L
≈ 0.029 mol/L