Given,

Triple point of Neon (T_Neon) = 23.57 K

Triple point of Carbon dioxide (T_{Carbon dioxide}) = 216.55 K

We know,

T_c = T_k – 273.15

Where, T_c is temperature in Celsius scale

T_k is temperature in Kelvin scale

Also,

T_f = (9/5)T_c + 32

Where, T_f is temperature in Fahrenheit scale

For Neon:

T_k = 24.57 K

∴ T_c = T_k – 273.15

⇒ T_c = 23.57 – 273.15

⇒ T_c = -248.58 °C

And T_f = (9/5)T_c + 32

⇒ T_f = (9/5)(-248.58) + 32

⇒ T_f = -447.44 + 32

⇒ T_f = -415.44°F

For Carbon dioxide:

T_k = 216.55 K

∴ T_c = T_k – 273.15

⇒ T_c = 216.55 – 273.15

⇒ T_c = -56.6 °C

And T_f = (9/5)T_c + 32

⇒ T_f = (9/5)(-56.6) + 32

⇒ T_f = -101.88 + 32

⇒ T_f = -69.88 °F

NOTE: The triple point of a substance is the temperature and pressure at which the three phases (gas, liquid, and solid) of that substance coexist in thermodynamic equilibrium.