What is the maximum number of emission lines when the excited electron of an H atom in n = 6 drops to the ground state?

Given:

Present State of Electron = 6


When an electron drops from nth shell to ground state, the number of lines produced is given by = {n× [n-1]} / 2


So, in the question the electron drops from 6th state to ground state.


So, number of lines produced in this transition is = {6× [6-1]}/2


=15


So, the lines produce in the transition is shown as below:



15