Calculate the wave number for the longest wavelength transition in the Balmer series of atomic hydrogen.
By referring to Balmer Formula:
We know that
Wave Number
For Balmer series, the values of n1 = 2 and the value of Rh = 109678
Wave number is inversely proportional to the wavelength of light. So for light of long wavelength, wave number has to be minimum. For minimum condition the value of n2 should be equal to 3.
Wave Number
= [109678×5] / 36
= 548390 / 36
= 15233.0556 cm-1
Therefore, the wave number for longest wavelength is 15.233× 103 cm-1.