The diameter of zinc atom is 2.6 Å. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.
Given:
Diameter of carbon atom = 2.6 Å
Radius of carbon atom = [2.6 / 2] = 1.3 Å
Length of line = 1.6 cm
Number of carbon atoms which can be place along the line is given by n = [1.6× 10-2] / [2.6× 10-10]
n = 61.538× 106
Therefore, the number of carbon atoms which can be place along the line is 61.538× 106.