An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.
Given:
Mass Number = 37
Percentage of neutron = 11.1% more as compared electrons
Let Number of electrons = number of protons = p
Let number of protons = p
Let number of neutrons= n
p + n = 81
p + {p + [11.1× p] / 100} = 37
p + 1.111p = 37
2.111p = 37
p = 37 / 2.111
p = 17.527
p = 17
Atomic Number = 17
The element is chlorine.
The atomic symbol is 3717Cl.