In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of 3.15 × 10–18 J from the radiations of 600 nm, calculate the number of photons received by the detector.

Given:

Energy, E = 3.15 × 10–18 J


Wavelength, λ = 600 nm


By Planck’s relation we have,


Energy, E = h×v


But we know v = [c] / [λ]


Where


c = Speed of Light


v= Frequency


λ = Wavelength


So, E = hc /λ


= [[6.626×10-34] × [3×108]] / [600×10-9]


= [1.9878×10-25] / [600×10-9]


= 3.313×10-19 J


Therefore, number of photons received = [3.15 × 10–18] / [3.313×10-19]


= 9.5


Therefore, the number of photons received cannot be in fraction


So, number of photons received is 9.


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