The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 105 ms–1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.
Given:
Velocity of ball, v = 4.37 × 105 ms–1
Mass of ball, m = 0.1kg
According to the de Broglie’s Equation:
λ = h/mv
Where,
λ = wavelength of moving particle
m = mass of electron
v= velocity of particle
h= Planck’s constant [6.62× 10-34]
λ = {[6.62× 10-34] / [0.1] × [4.37 × 105]}
= {[6.62× 10-34] / [43.7 × 103]
= 1.516× 10-38 m
Therefore, the wavelength is 1.516× 10-38 m.