Indicate the number of unpaired electrons in:
(a) P - 1s2 2s2 2p6 3s2 3p3
(b) Si - 1s2 2s2 2p6 3s2 3p2
(c) Cr - 1s2 2s2 2p6 3s2 3p6 4s1 3d5
(d) Fe - 1s2 2s2 2p6 3s2 3p6 4s2 3d6
(e) Kr - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
(a) Therefore, number of unpaired electron = 3
(b) Therefore, number of unpaired electron = 2 [as p orbital can have a maximum of 6 electrons]
(c) Therefore, number of unpaired electron = 6
(d)Therefore number of unpaired electron = 4
(e) Krypton has no unpaired electron as it is noble gas.