Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP: 1 atmospheric pressure, 0 °C). Show that it is 22.4 litres.
Given:
P = 1 atm = 101 kPa
T = 273.15 K
n = 1 mole
V = ?
Explanation: We know that the volume occupied by 1 mole of oxygen gas at STP = 22.4 litres. By using the Ideal Gas Law (PV = nRT) we can obtain the required result.
Wkt…
PV = nRT ---( Ideal Gas Law )
∴ V = 
⇒ V = 
≈ 0.0224 m3 = 22.4 litres
⇒ V = 22.4 litres
The required volume is 22.4 litres.
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