Find the centre and radius of the circles x2 + y2 – 4x – 8y – 45 = 0.


The given equation is

x2 + y2 – 4x – 8y – 45 = 0

or (x2 – 4x) + (y2 – 5y) = 45

Now completing the squares with in the parenthesis, we get

(x2 – 4x + 4)+(y2 –8y + 16) = 4 + 16 + 45

or (x - 2)2 + (y – 4)2 = 65

Therefore, the given circle has centre at (2, 4) and radius .

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