Lakhmir Singh & Manjit Kaur - Physics

Book: Lakhmir Singh & Manjit Kaur - Physics

Chapter: 3. Sources of Energy

Subject: Physics - Class 10th

Q. No. 37 of Multiple Choice Questions (MCQs)-Pg-141

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If the solar constant is 1.4 kW/m2, then the solar energy received by 1 m2 area in one hour is :

From the solar constant we deduce that

1.4 kW of power is incident upon every 1m2 of area.

i.e. the total energy incident in 1 hr over an area of 1 m2 will be

= 1.4 kW x 1 hr

(Since P=E/t or E=P x t)

Hence, energy = 1.4 kWh

Converting into Kj we get 5040 Kj)

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