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If the solar constant is 1.4 kW/m2, then the solar energy received by 1 m2 area in one hour is :
From the solar constant we deduce that
1.4 kW of power is incident upon every 1m2 of area.
i.e. the total energy incident in 1 hr over an area of 1 m2 will be
= 1.4 kW x 1 hr
(Since P=E/t or E=P x t)
Hence, energy = 1.4 kWh
Converting into Kj we get 5040 Kj)