A vessel of 120 mL capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35°C. What would be its pressure?
Given,
Initial pressure, P1 = 1.2 bar
Initial volume, V1 = 120 ml
Final volume, V2 = 180 ml
Since the temperature remains constant, the final pressure (P2) can be calculated using
Boyle's law.
According to Boyle's law,
P1V1 = P2V2
P1V1 = P2V2
⇒ 
⇒ P2 = 
⇒ P2 = 2.5 bar
Therefore, the pressure would be 0.8 bar.
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