Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.

(R = 0.083 bar dm3 K–1 mol–1).

Given:

Number of moles, n = 4


Volume, V = 5 dm3


Pressure, P = 3.32 bar


Universal gas constant, R = 0.083 bar dm3 K–1 mol–1


Let the temperature be T.


Then, from ideal gas equation we know that: -


PV = nRT




= 50K


Hence, the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar is 50K.


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