Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol –1 K –1 .

Question

Philoid · Accepted Answer

We Know that,

Q = ncΔT

Where n is number of mole of substance

c is molar heat capacity of substance

ΔT is rise in temperature

Given,

c = 24 J mol^-1 K^-1

ΔT = 55 – 35 = 20°C = 20 K

m = 60 g

number of mole of Aluminium in m gram is given as

n = m/M

Where M is molar mass of aluminium.

∴ n = 60/27 = 2.22

Thus Q = ncΔT

= (2.22 mol)×(24 J mol^–1 K^–1)×(20K)

= 1065.6 J

= 1.065 kJ

Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol–1 K–1.

Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol^–1 K^–1.