For the following equilibrium, K c = 6.3 × 10 14 at 1000 K NO (g) + O 3 (g) ⇌ NO 2 (g) + O 2 (g) Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is K c , for the reverse reaction?

Question

Philoid · Accepted Answer

Equilibrium constant for forward reaction is

K_c^fwd =

For reverse reaction, Equilibrium constant is given as,

K_c^rev =

= 1/K_c^fwd

= 1/6.3×10¹⁴

= 1.59 × 10^-15

[(Equilibrium constant for reverse reaction) = 1/(equilibrium constant of forward reaction)

i.e, K_c^rev = ]

For the following equilibrium, Kc= 6.3 × 1014 at 1000 KNO (g) + O3 (g) ⇌NO2 (g) + O2 (g)Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

For the following equilibrium, K_c= 6.3 × 10¹⁴ at 1000 K
NO (g) + O₃ (g) ⇌NO₂ (g) + O₂ (g)

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is K_c, for the reverse reaction?