Nitric oxide reacts with Br2 and gives nitrosyl bromide as per reaction given below:
2NO (g) + Br2 (g) ⇌2NOBr (g)
When 0.087 mol of NO and 0.0437 mol of Br2 are mixed in a closed container at constant temperature, 0.0518 mol of NOBr is obtained at equilibrium. Calculate equilibrium amount of NO and Br2.
The chemical reaction is,
Initial amount:
Let x amount of Br2 be reacted to attain equilibrium. Then amount of substance left at equilibrium,
2NO (g) + Br2 (g) ⇌2NOBr (g)
Equilibrium amount: 0.087 – 2x 0.0437 – x 2x
Given, equilibrium concentration of NOBr is 0.0518,
i.e, 2x = 0.0518
x = 0.0259
Thus,
Amount of NO at equilibrium = 0.087 - 2 × 0.0259
= 0.0352 mole
Amount of Br2 at equilibrium = 0.0437 – 0.0259
= 0.0178 mole