A sample of pure PCl5 was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl5 was found to be 0.5 × 10–1 mol L–1. If value of Kc is 8.3 × 10–3, what are the concentrations of PCl3 and Cl2 at equilibrium?
PCl5 (g) ⇌ PCl3 (g) + Cl2(g)
For the given reaction, let’s assume that the initial molar concentration of PCl5 is x mol/L.
The given reaction is:
Moles of PCl5 decomposed during the reaction=Moles of PCl3 formed=Moles of Cl2 formed=(x-0.05) mol/L
Equilibrium constant (Kc) is defined as a number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.
Here, Kc = 0.0083
For the given reaction,
Where, [PCl3] = concentration of PCl3 in mol/L at equilibrium
[Cl2] = concentration of Cl2 in mol/L at equilibrium
[PCl5] = concentration of PCl5 in mol/L at equilibrium
(x-0.05)2 = 0.000415
(x-0.05) = 0.0203
x = 0.07 mol/L
Therefore, [PCl3] = (x-0.05) = 0.07-0.05 = 0.02 mol/L
[Cl2] = (x-0.05) = 0.07-0.05 = 0.02 mol/L