Assign oxidation number to the underlined elements in each of the following species:
K2MnO4
Let the oxidation number(O.N.) of Mn be ‘x’
We know that,
O.N. of K = + 1
O.N. of O = -2
Therefore, we have,
2(+1) + 1(x) + 4(-2) = 0
2 + x-8 = 0
X = + 6
The O.N. of Mn is + 6.