Assign oxidation number to the underlined elements in each of the following species:

K2MnO4

Let the oxidation number(O.N.) of Mn be ‘x’


We know that,


O.N. of K = + 1


O.N. of O = -2


Therefore, we have,


2(+1) + 1(x) + 4(-2) = 0


2 + x-8 = 0


X = + 6


The O.N. of Mn is + 6.


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