Assign oxidation number to the underlined elements in each of the following species:
NaBH4
Let the oxidation number(O.N.) of B be ‘x’
We know that,
O.N. of Na = + 1
O.N. of H = -1
Therefore , we have,
1(+ 1) + 1(x) + 4(-1) = 0
1 + x-4 = 0
X = + 3
The O.N. of B is + 3.