Balance the following redox reactions by ion – electron method:

H2O2 (aq) + Fe2+ (aq) → Fe3+ (aq) + H2O (l) (in acidic solution)

Following the steps as in part (A), we have the oxidation half reaction equation as:-


Fe2+(aq)→ Fe3+(aq) + e-


And the reduction half reaction as:-


H2O2(aq) + 2H+(aq) + 2e-→ 2H2O


Multiplying the oxidation half reaction by 2 and then adding it to the reduction half reaction, we have the net balanced redox reaction as:-


H2O2(aq) + 2Fe2+(aq) + 2H+(aq)→ 2 Fe3+(aq) + 2H2O


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