In the estimation of sulphur by Carius method, 0.468 g of an organic Sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of Sulphur in the given compound.

Given:


Total mass of organic compound=0.468g


Mass of barium sulphate formed=0.688g


Since, 1 mol of BaSO4=233g of BaSO4=32g of sulphur


{molecular wt. Of Ba=137g, S=32g, O=16g}


{So, Molecular wt. Of BaSO4 =137+32+4(16)=233g}


Thus, 0.688g of BaSO4 contains g of sulphur=0.0917g of sulphur.


Therefore, percentage of sulphur==19.59%


Hence, the percentage of sulphur in the given compound is 19.59%


36