In ΔABC, it is given that DE || BC. If AD = 3 cm, DB = 2 cm and DE = 6 cm, then BC = ?

In ΔADE and ΔABC


ADE = ABC [Corresponding angles as DE || BC]


AED = ACB [Corresponding angles as DE || BC]


ΔADE ~ ΔABC [By Angle-Angle Similarity criterion]


[Corresponding sides of similar triangles are in the same ratio]


Now,


Given, AD = 3 cm


DB = 2 cm


DE = 6 cm


AB = AD + DB = 3 + 2 = 5 cm


Using this in above equation,



BC = 10 cm

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