If tan θ = √3, then
Given,
tan θ = √3
⇒ tan2θ = 3
⇒ sec2θ - 1 = 3 [As tan2θ + 1 = sec2θ]
⇒ sec2θ = 4 …[1]
Also,
⇒ as tanθ = √3
Squaring both sides,
[As cot2θ + 1 = cosec2θ]
…[2]
Putting the values from [1] and [2] into given eqn