If 3 cos2θ + 7sin2θ = 4, show that cotθ = √3

Given,


3cos2θ + 7sin2θ = 4


3cos2θ + 3sin2θ + 4sin2θ = 4


3(cos2θ + sin2θ) + 4sin2θ = 4


3 + 4sin2θ = 4


[as sin2θ + cos2θ = 1]


4sin2θ = 1




θ = 30°


[as ]


cot θ = √3


[ as cot 30° = √3]


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