In the given figure, DE|| AC and DF || AE.
Prove that:
DE || AC [Given]
And we know, By Basic Proportional Theorem
If a line is drawn parallel to the one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in same ratio
…[1]
And DF || AE
By Basic Proportional Theorem,
[From [1]]
Hence, Proved