In the given figure, DE|| AC and DF || AE.


Prove that:

DE || AC [Given]


And we know, By Basic Proportional Theorem


If a line is drawn parallel to the one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in same ratio


…[1]


And DF || AE


By Basic Proportional Theorem,



[From [1]]



Hence, Proved


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