Evaluate:
Using cosec(90° - θ) = secθ
and cot(90° - θ) = tanθ
we have,
Now, sin(90 - θ) = cos θ and
tan(90 - θ) = cot θ we have
[ Since,
tan2θ - sec2θ = 1
sin2θ + cos2θ = 1
tan 60° = √3]