Evaluate:
Given: …Equation 1
We know
sec θ = cosec (900 – θ)
tan θ = cot (900 – θ)
sin θ = cos (900 – θ)
Using the above three relations in Equation 1 we get
We also know
sin2 θ + cos2 θ = 1
⇒ sin2 55 + cos2 55 = 1
And,
∴
⇒