Prove that: (sin θ – cosec θ)(cos θ – sec θ) =

To Prove: (sin - cosec)(cos- sec) =


L.H.S. = (sin θ –cosec θ)(cos θ- sec θ)




Since sin2θ + cos2θ = 1 , So



After Cancellation we get


L.H.S. = sin θ cos θ


Dividing the numerator and denominator with cos θ we get



We know



Since sec2θ = 1 + tan2θ



Dividing The Numerator and denominator by tan θ we get



Since


= R.H.S


Since L.H.S. = R.H.S


Hence Proved


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