If U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {2, 4, 6, 8} and B = {2, 3, 5, 7}. Verify that
(i) (A ∪ B)’ = A’ ∩ B’ (ii) (A ∩ B)’ = A’ ∪ B’
(i) First solving for left hand side,
(A ⋃ B)’ = U - (A ⋃ B)
First we find (A ⋃ B),
(A ⋃ B) = {2, 4, 6, 8} ⋃ {2, 3, 5, 7}
⇒ (A ⋃ B) = {2, 3, 4, 5, 6, 7, 8}
Now,
(A ⋃ B)’ = U - (A ⋃ B)
⇒ (A ⋃ B)’ = {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 4, 5, 6, 7, 8}
⇒ (A ⋃ B)’ = {1, 9}
Now, solving for right hand side,
A’ = U - A
A’ = {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 4, 6, 8}
A’ = {1, 3, 5, 7, 9}
B’ = U - B
B’ = {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 5, 7}
B’ = {1, 4, 6, 8, 9}
A’ ⋂ B’ = {1, 3, 5, 7, 9} ⋂ {1, 4, 6, 8, 9}
⇒ A’ ⋂ B’ = {1, 9}
∴ LHS = RHS, Hence verified.
(ii) First solving for left hand side,
(A ⋂ B)’ = U - (A ⋂ B)
First we find (A ⋂ B),
(A ⋂ B) = {2, 4, 6, 8} ⋂ {2, 3, 5, 7}
⇒ (A ⋂ B) = {2}
Now,
(A ⋂ B)’ = U - (A ⋂ B)
⇒ (A ⋂ B)’ = {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2}
⇒ (A ⋂ B)’ = {1, 3, 4, 5, 6, 7, 8, 9}
Now, solving for right hand side,
A’ = U - A
A’ = {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 4, 6, 8}
A’ = {1, 3, 5, 7, 9}
B’ = U - B
B’ = {1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 5, 7}
B’ = {1, 4, 6, 8, 9}
A’ ⋃ B’ = {1, 3, 5, 7, 9} ⋃ {1, 4, 6, 8, 9}
⇒ A’ ⋃ B’ = {1, 3, 4, 5, 6, 7, 8, 9}
∴ LHS = RHS, Hence verified.