If X and Y are two sets such that X has 40 elements, X ∪ Y has 60 elements and X ∩ Y has 10 elements, how many elements does Y have?
Given-
n(X) = 40, n(X ∩ Y) = 10, and n(X ∪ Y) = 60
We know that-
n(X ∪ Y) = n(X)+ n(Y) - n(X ∩ Y)
⇒ 60 = 40+n(Y) - 10
⇒ 60 = 30+n(Y)
⇒ n(Y) = 60-30
∴ n(Y) = 30
Thus, the no. of elements in n(Y) is 30.