Show that the points (–2, 3, 5), (1, 2, 3) and (7, 0, –1) are collinear.
If three points are collinear, then they lie on a line.
Let first calculate distance between the 3 points
i.e. PQ, QR and PR
Calculating PQ
P ≡ (– 2, 3, 5) and Q ≡ (1, 2, 3)
Distance PQ
Here,
x1 = – 2, y1 = 3, z1 = 5
x2 = 1, y2 = 2, z2 = 3
Distance PQ
Calculating QR
Q ≡ (1, 2, 3) and R ≡ (7, 0, – 1)
Distance QR
Here,
x1 = 1, y1 = 2, z1 = 3
x2 = 7, y2 = 0, z2 = – 1
Distance QR
Calculating PR
P ≡ (– 2, 3, 5) and R ≡ (7, 0, – 1)
Distance PR
Here,
x1 = – 2, y1 = 3, z1 = 5
x2 = 7, y2 = 0, z2 = – 1
Distance PR
Thus, PQ = , QR = & PR =
So, PQ + QR = + = = PR
Thus, Points P, Q and R are collinear.