Sum of the first p, q and r terms of an A.P. are a, b and c, respectively.
Prove that 
Let a1 and d be the common difference of the A.P.
Given,
Sum of first p terms = ![]()
⇒ ![]()
Sum of first q terms = ![]()
⇒ ![]()
Sum of first p terms = ![]()
⇒ ![]()
Subtracting (II) from (I)
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⇒ ![]()
⇒ ![]()
Subtracting (III) from (II)
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⇒ ![]()
⇒ ![]()
From (IV) and (V)
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⇒ pq (p – q) (2br – 2cq) = qr (q – r) (2aq – 2bp)
⇒ p (p – q) (2br – 2cq) = r (q – r) (2aq – 2bp)
⇒ (aqr – bpr) (q – r) = (bpr – cpq) (p – q)
Dividing both sides by pqr
⇒ ![]()
⇒ ![]()
⇒ ![]()
Hence, proved.