Sum of the first p, q and r terms of an A.P. are a, b and c, respectively.
Prove that
Let a1 and d be the common difference of the A.P.
Given,
Sum of first p terms =
⇒
Sum of first q terms =
⇒
Sum of first p terms =
⇒
Subtracting (II) from (I)
⇒
⇒
Subtracting (III) from (II)
⇒
⇒
From (IV) and (V)
⇒ pq (p – q) (2br – 2cq) = qr (q – r) (2aq – 2bp)
⇒ p (p – q) (2br – 2cq) = r (q – r) (2aq – 2bp)
⇒ (aqr – bpr) (q – r) = (bpr – cpq) (p – q)
Dividing both sides by pqr
⇒
⇒
⇒
Hence, proved.