Sum of the first p, q and r terms of an A.P. are a, b and c, respectively.

Prove that

Let a1 and d be the common difference of the A.P.


Given,


Sum of first p terms =



Sum of first q terms =



Sum of first p terms =



Subtracting (II) from (I)





Subtracting (III) from (II)





From (IV) and (V)



pq (p – q) (2br – 2cq) = qr (q – r) (2aq – 2bp)


p (p – q) (2br – 2cq) = r (q – r) (2aq – 2bp)


(aqr – bpr) (q – r) = (bpr – cpq) (p – q)


Dividing both sides by pqr





Hence, proved.


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