Find the sum to indicated number of terms in each of the geometric progressions in
1, – a, a2, – a, ... n terms (if a – 1).
Given: 1, – a, a2, – a, ... n terms
Sum of n terms of a G.P. is given by: (a: First term of G.P, r: common difference of G.P, n: Number of terms of the G.P)
First term of the Given G.P (a) = 1
Common difference of the given G.P(r) = = -a
Number of terms(n): n
Let the sum of n terms be s
∴ s =
⇒ s =
⇒ s = [
∴ The sum of n terms of the given sequence is: [1-(-a)n]