How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?

Given: G.P. 3, 32, 33, … and Sum = 120


Here a = 3 and r = = 3


The Sum of terms in G.P. is given by:


= 120


= 120


= 120(2)


= 240


= = 80


3n = 80 +1 = 81


3n = 81


Applying ln on both sides, we get





n = 4


16