How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?
Given: G.P. 3, 32, 33, … and Sum = 120
Here a = 3 and r = = 3
The Sum of terms in G.P. is given by:
∴ = 120
⇒ = 120
⇒ = 120(2)
⇒ = 240
⇒ = = 80
⇒ 3n = 80 +1 = 81
⇒ 3n = 81
Applying ln on both sides, we get
⇒
⇒
⇒ n = 4