Find a G.P. for which sum of the first two terms is – 4 and the fifth term is 4 times the third term.
Given: S2 = —4 and a5 = 4 × a3
The Sum of terms in G.P. is given by:
∴ S2 = = —4
⇒ = —4
⇒ a(1+r) = —4 –1
Here,
a5 = 4 × a3
⇒ ar4 = 4 × ar2 (∵ nth term of the G.P is arn-1)
⇒ r2 = 4
⇒ r = 2
∴ r = +2 or –2
Case 1: r = +2
From eq –1
a(1+r) = —4
⇒ a(1+2 ) = —4
⇒ a =
∴ G.P :
Case 2: r = –2
From eq –1
a(1+r) = —4
⇒ a(1+(–2) ) = —4
⇒ a = = 4
∴ G.P : 4 , –8, 16, –32,…….
∴ The possible G.P ‘s are or 4 , –8, 16, –32,…….