If the 4th, 10th and 16th terms of a G.P. are x, y and z, respectively. Prove that x, y, z are in G.P.

Given: 4th, 10th and 16th terms of a G.P. are x, y and z, respectively


Let a be the first term and r be the common ratio of the G.P.


Here,


We know that nth term of the G.P is given by arn-1



a4 = ar3 = x —1


a10 = ar9 = y —2


a16 = ar15 = z —3


Dividing eq-(2) by eq-(1), we obtain




Dividing eq(3) by eq-(2), we obtain




That is


Thus, x, y, z are in G. P


19