A G.P. consists of an even number of terms. If the sum of all the terms is 6 times the sum of terms occupying odd places, then find its common ratio.

Let the terms of G.P. be T1, T2, T3, T4, … T2n.


Number of terms = 2n


According to question,


T1 + T2 + T3 + … + T2n = 6 [T1 + T3 + … + T2n–1]


T1 + T2 + T3 + … + T2n – 6 [T1 + T3 + … + T2n–1] = 0


T2 + T4 + … + T2n = 4 [T1 + T3 + … + T2n–1]


Let the G.P. be a, ar, ar2, ar3, …



ar = 4a


r = 4


Thus, the common ratio of the G.P. is 4.


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