Let 0 = r cos θ and 1 = r sin θ……….(i)

Squaring both sides, we get

0= r² cos² θ and 1 = r² sin² θ

Adding both the equations, we get

0 + 1 = r² cos² θ + r² sin² θ

⇒ 1 = r² (cos² θ + sin² θ)

⇒ 1 = r² or r² = 1 [∵ sin² θ + cos² θ = 1]

⇒ r = √1

⇒ r = 1 (conventionally, r>0)

Substituting r = √2 in (i), we get

0 = cos θ and 1 = sin θ

⇒ cos θ = 0 and sin θ = 1

⇒ θ = cos^-1 0 and θ = sin^-1 1

∵ We know that the complex number i lies on the imaginary axis (y-axis) and the value of the argument lies between - π and π, i.e. - π < θ ≤ π.

As we know that the polar representation of a complex number z = x + iy is

z = r (cos θ + i sin θ) where is the modulus of the complex number and θ is the argument of the complex number, denoted by arg z.

So, the required polar form is .