In each of the following, find the equation of the circle with

Centre () and radius (1/12)

The equation of a circle with centre (h,k) and radius r is given as


(x-h)2 + (y-k)2=r2


It is given that centre (h,k)= and radius(r) = .


Therefore, the equation of the circle is



x2 – x + + y2 -


x2 – x + + y2 -


x2 – x + + y2 -=0


144x2 -144x + 36 + 144y2 -72y + 9- 1=0


144x2 -144x+ 144y2 – 72y + 44 =0


36x2 +36x+ 36y2 -18y+11 = 0


36x2 +36y2 -36x – 18y+ 11= 0


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